PERMUTATION VIA CANVA CODING

Permutations Lesson - Slide 1

Understanding Permutations

Introduction

📚 What Are Permutations?

Definition

A permutation is an arrangement of objects in a specific order. The key word here is order - changing the order creates a different permutation.

💡 Key Insight: In permutations, ABC is different from BAC. Order matters!

Real-Life Examples

  • Arranging books on a shelf
  • Seating arrangements at a dinner table
  • Creating passwords or PIN codes
  • Race finishing positions (1st, 2nd, 3rd)
  • Creating team lineups in sports
Permutations Lesson - Slide 2

Understanding Permutations

The Fundamental Concept

🔤 The Fundamental Concept

Let's Start Simple

Imagine you have 3 letters: A, B, and C. How many different ways can you arrange them?

A
B
C

All Possible Arrangements:

ABC | ACB | BAC | BCA | CAB | CBA

Total: 6 arrangements

The Logic Behind It

  • For the 1st position: we have 3 choices (A, B, or C)
  • For the 2nd position: we have 2 choices (remaining letters)
  • For the 3rd position: we have 1 choice (last letter)
Total arrangements = 3 × 2 × 1 = 6
💡 This multiplication principle is the foundation of all permutation problems!
Permutations Lesson - Slide 3

Understanding Permutations

Factorial Notation

🔢 Factorial Notation (n!)

To make our lives easier, mathematicians created a special notation called factorial.

n! = n × (n-1) × (n-2) × ... × 2 × 1

Examples:

  • 3! = 3 × 2 × 1 = 6
  • 4! = 4 × 3 × 2 × 1 = 24
  • 5! = 5 × 4 × 3 × 2 × 1 = 120
  • 10! = 10 × 9 × 8 × ... × 2 × 1 = 3,628,800
⚠️ Special Case: By definition, 0! = 1 (this makes mathematical formulas work correctly!)

General Formula for Permutations

The number of ways to arrange n different objects is:

P(n) = n!
Permutations Lesson - Slide 4

Understanding Permutations

Slide 4 of 12 - Practice Question 1

Slide 4 of 12

✏️ Practice Question 1

Question:

In how many ways can 5 students be arranged in a row for a photograph?

Permutations Lesson - Slide 5

Understanding Permutations

Slide 5 of 12 - Selecting and Arranging (nPr)

Slide 5 of 12

🎲 Selecting and Arranging (nPr)

Often, we don't use all objects. We select r objects from n objects and arrange them.

The Formula:

nPr = n! / (n - r)!

Where:

  • n = total number of objects
  • r = number of objects to arrange
  • nPr = number of permutations

Example: Racing Medals

In a race with 8 runners, how many ways can we award Gold, Silver, and Bronze medals?

  • n = 8 (total runners)
  • r = 3 (positions to fill)
  • 8P3 = 8! / (8-3)! = 8! / 5!
  • = (8 × 7 × 6 × 5!) / 5!
  • = 8 × 7 × 6 = 336 ways
💡 Tip: You can cancel out factorials to simplify calculations!
Permutations Lesson - Slide 6

Understanding Permutations

Slide 6 of 12 - Practice Question 2

Slide 6 of 12

✏️ Practice Question 2

Question:

A company has 10 employees. In how many ways can they select a President, Vice President, and Secretary?

Permutations Lesson - Slide 7

Understanding Permutations

Slide 7 of 12 - Circular Permutations

Slide 7 of 12

⭕ Circular Permutations

When objects are arranged in a circle, some arrangements that look different in a line are actually the same in a circle.

The Formula:

Circular permutations of n objects = (n - 1)!

Why (n-1)! ?

In a circle, we can fix one person's position (say at "12 o'clock") and arrange the others relative to them. This eliminates rotational duplicates.

Example: 5 people around a circular table = (5-1)! = 4! = 24 ways

💡 Real-life applications: Round table seating, necklace designs, circular relay races
Permutations Lesson - Slide 8

Understanding Permutations

Slide 8 of 12 - Practice Question 3

Slide 8 of 12

✏️ Practice Question 3

Question:

In how many ways can 6 friends sit around a circular dining table?

Permutations Lesson - Slide 9

Understanding Permutations

Slide 9 of 12 - Permutations with Restrictions

Slide 9 of 12

🚫 Permutations with Restrictions

Sometimes we have conditions or restrictions in our arrangements. Let's see how to handle these!

Example 1: Objects Must Stay Together

Problem: How many ways can we arrange the letters A, B, C, D, E if B and C must be together?

  • Step 1: Treat B and C as one unit: (BC)
  • Step 2: Now we have 4 objects: A, (BC), D, E
  • Step 3: Arrange these 4 objects: 4! = 24 ways
  • Step 4: B and C can switch within their unit: 2! = 2 ways
  • Total: 24 × 2 = 48 ways

Example 2: Specific Positions

Problem: Arrange 5 people where person A must be at the beginning.

  • Step 1: Fix A in the first position (1 way)
  • Step 2: Arrange the remaining 4 people: 4! = 24 ways
  • Total: 24 ways
Permutations Lesson - Slide 10

Understanding Permutations

Slide 10 of 12 - Practice Question 4

Slide 10 of 12

✏️ Practice Question 4

Challenge Question:

How many 4-digit numbers can be formed using digits 1, 2, 3, 4, 5, 6 (without repetition) where the number must be even?

Permutations Lesson - Slide 11

Understanding Permutations

Quick Reference Summary

📝 Quick Reference Summary

1. Basic Permutation: n! = n × (n-1) × (n-2) × ... × 1
2. Selecting r from n: nPr = n! / (n-r)!
3. Circular Permutations: (n-1)!

Key Things to Remember:

  • ✓ Order matters in permutations
  • ✓ Use factorial notation to simplify calculations
  • ✓ Cancel common factorials in nPr formulas
  • ✓ For circular arrangements, use (n-1)!
  • ✓ Break down restriction problems step by step
  • ✓ Identify if objects must stay together or apart
🎓 Final Advice: Practice is key! The more problems you solve, the easier pattern recognition becomes. Always draw diagrams for complex problems!
Permutations Lesson - Slide 12

Understanding Permutations

Slide 12 of 12 - Final Challenge

Slide 12 of 12

🏆 Final Challenge Question

Comprehensive Question:

In how many ways can 7 books be arranged on a shelf if 2 specific books must NOT be next to each other?

🎉 Congratulations on completing the lesson! You now have the tools to solve permutation problems with confidence.

Comments