Quiz: Quadratic Equations – Three Methods of Solving

🧠 Quiz: Quadratic Equations – Three Methods of Solving

1. Solve \(x^2 - 5x + 6 = 0\) by factoring.

\(x = 2, 3\) \(x = -2, -3\) \(x = 1, 6\) \(x = -1, -6\)

2. Which of the following is the quadratic formula?

\(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) \(\frac{-a \pm \sqrt{a^2 - 4bc}}{2b}\) \(\frac{-c \pm \sqrt{c^2 - 4ab}}{2a}\) \(\frac{-b \pm \sqrt{a^2 - 4bc}}{2c}\)

3. Solve \(x^2 + 7x + 12 = 0\) by factoring.

\(x = -3, -4\) \(x = 3, 4\) \(x = -2, -6\) \(x = 2, 6\)

4. The discriminant of \(x^2 - 4x + 4 = 0\) is:

0 4 8 16

5. Solve \(x^2 - 9 = 0\).

\(x = 3, -3\) \(x = 9, -9\) \(x = 0, 9\) \(x = -1, 9\)

6. Which method is BEST when the quadratic cannot be factored easily?

Factoring Completing the square Trial and error Graphing only

7. Solve \(2x^2 - 8x + 6 = 0\) using the quadratic formula.

\(x = 1, 3\) \(x = -1, -3\) \(x = 2, 6\) \(x = -2, -6\)

8. What is the axis of symmetry for \(y = x^2 - 6x + 5\)?

\(x = 3\) \(x = -3\) \(x = 5\) \(x = -5\)

9. Solve \(x^2 + 2x - 8 = 0\) by factoring.

\(x = -4, 2\) \(x = 4, -2\) \(x = -2, 8\) \(x = 2, 8\)

10. If the discriminant is negative, the quadratic equation has:

Two real roots One real root Two complex roots No solution